A force of 4 newton act on a body of mass 2 kg for 4 second assuming the body to initially at rest find it velocity when the force stop acting (, b) distance covered in 10 second afterthe the force starts acting
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accn = F / m= 2
v= at = 2× 4 = 8
s= 1/2× a × t ^2= 16 m
v= at = 2× 4 = 8
s= 1/2× a × t ^2= 16 m
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