A force of 4 newton acts on a body of mass 2 kg for 4 seconds if the initial velocity is zero find its velocity when the force stops acting
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Answer:
v = 8 m/s
Explanation:
F = 4 N & m = 2 kg & u = 0 m/s & t = 4s & v = ?
F = m a ⇒ a = F / m
a = 4 / 2 = 2 m/s²
v = u + at
v = 0 + 2x4
v = 8 m/s
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