A force of 40 N acting on a body at an angle of 60 degree with the horizontal direction displaces the body through a distance of 5m along the surface of a floor. calculate the work done.
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Given :
- Force Applied on the body = 40 N
- Angle between direction of force and displacement = 60°
- Displacement = 5 m
To Find :
⠀⠀⠀⠀⠀⠀⠀The work done on the body.
Solution :
To find the work done , let's know about some of the cases of work done :-
- If θ < 90° , then the work done will be positive as cos θ > 0 , when 0° < θ < 90°.
- If θ > 90° , then the work done will be negative as cos θ < 0 , when 90° < θ < 180° .
- If θ = 90° , then the work done will be equal to zero as cos 90° = 0.
Here , we know the θ (i.e, 60°) is less than 90°.
Hence, the work done by the body will be positive.
We know the formula for work done .i.e,
Where :-
- W = Work Done.
- F = Force Applied.
- s = Displacement.
- θ = Angle between direction of force and displacement.
Using the formula and substituting the values in it, we get :-
Hence, the work done on the body is 100 J.
Answered by
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Question:-
A force of 40 N acting on a body at an angle of 60 degree with the horizontal direction displaces the body through a distance of 5m along the surface of a floor. calculate the work done.
Formula to be used:-
⟹W=Fscosθ
Solution:-
️ ➭ W = Fscosθ
️ ➭ W = 40 × 5 × cos 60°
️ ➭ W = 200 . 1/2
️ ➭ W = 100J
☞ Hence verified
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