Question

A force of 40 N applied on a nail. If the pressure produced on the tip is 4×${10}^{8}N {m}^{2}$ Then calculate the area of cross section of the Tip .

(Please give a correct answer)

Answer 1

Pressure= Force*Area

Given,

Pressure=4*10^8

Force=40N

4*10^8=40*Area

Area=10^-7 m^2

=10^-5 m^2

Here ^ means Power

Answer 2

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✴ F = 40 N
✴ A = ?
✴ P = 4×${10}^{8}N {m}^{2}$

■ According to the formula

□ P = $\frac{F}{A}$

□4×${10}^{8}$ = $\frac{40}{A}$

□ A = $\frac{40}{4×{10}^{8}}$

□ A = $\frac{10}{{10}^{8}}$

□ A = $\frac{1}{{10}^{7}}$

□ A = ${1}×{10}^{-7}$ ...... OR

□ A = ${10}^{-7}{m}^{2}$ ANS


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Hope this helps. . . . . . . . ☺☺