Question

A force of 40 N is applied on a body at rest of mass 5 Kg for 3 seconds . Calculate the velocity of the body when the force stops acting

Answer 1

$\huge \fbox {f = ma}$

f=40N

m=5kg

40N=5kg(a)

a=40/5

a=8

$\huge \underline{ v_{2} = v_{1} + at}$

$v_{1} = 0 \frac{m}{s}$

$a = 8$

$t = 3s$

$\huge\underline{ v_{2} = 0 + 8 \times 3}$

$\huge \underline \pink{v_{2} = 24 \frac{m}{s} }$