Question

a force of 40 new ton acts on a mass of 5 kg at rest for seconds . find the final velocity of the body after 5 seconds​

Answer 1

Given :-

★ Force applied, F = 40 N

★ Mass, m = 5 kg

★ Time, t = 5 sec

★ Initial velocity, u = 0 m/s

To Find :-

★ What is the final velocity of the body after 5 sec?

Solution :-

At first, we have to find acceleration of the body.

We know, Newton's second law of motion

$\boxed{\rm F = ma}$

Where,

F = Force

m =Mass

a = Acceleration

Substituting the values, we get

⟹ 40 = 5 × a

⟹ a = 40/5 m/s

⟹ a =8m/s²

Therefore, acceleration of the body is = 8m/s²

From kinematic equation, we know

v = u + at

Now, put the given values

⟹ v = 0 + (8) × 5

⟹ v = 40 m/s

Hence,

final velocity of the body after 5 sec is = 40 m/s

Know more :-

1. What is acceleration?

✰ Acceleration is the rate of change of the velocity with respect to time.

2. What is force?

✰ It’s an act push and pull of an object.

Answer 2

Answer:

• The Final velocity (v) is 40 m/s

Given:

1. Force (F) = 40 N.
2. Mass (M) = 5 Kg.
3. Initial velocity (u) = 0 m/s.
4. Time period (t) = 5 secs.

Explanation:

$\rule{300}{1.5}$

From Newton's second law of motion we know,

$\large\bigstar\;\underline{\boxed{\sf F=Ma}}$

Here,

• F Denotes Force.
• M Denotes Mass.
• a Denotes acceleration.

substituting the values,

$\longrightarrow\sf F=M\times a\\\\\\\longrightarrow\sf F=M\times \Bigg\langle \dfrac{v-u}{t}\Bigg\rangle\ \ \ \ \because\Bigg[a=\dfrac{v-u}{t}\Bigg]\\\\\\\longrightarrow\sf 40=5\times \Bigg\langle \dfrac{v-0}{5}\Bigg\rangle\\\\\\\longrightarrow\sf 40=5\times \dfrac{v}{5}\\\\\\\longrightarrow\sf v = 40\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf v = 40\;m/s}}}}$

∴ The Final velocity (v) is 40 m/s.

$\rule{300}{1.5}$