Question

a force of 40 Newton acts on a body on a smooth surface then the body starts from rest and is observed to move hundred metres in 5 seconds mass of the body is

Answer 1

HEY BUDDY...!!!

HERE'S THE ANSWER..

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▶️ We'll note the given data from question


✔️ Where ,

⏺️F ( force ) = 40 N

⏺️ v ( final velocity ) = ?

⏺️a ( Acceleration ) = ?

⏺️m ( mass ) = ?

⏺️u ( initial velocity ) = 0 // rest

⏺️s ( displacement ) = 100 m

⏺️t ( time ) = 5 s


♠️ First we'll find v with

=> v = s / t

=> v = 100 / 5

=> [ v = 20 m / s ]

♠️ Now using [ v = u + a × t ] , we'll find a

=> v = u + a × t

=> a = ( v - u ) / t

=> a = ( 20 - 0 ) / t

=> a = 20 / 5

=> [ a = 4 m / s^2 ]


♠️ Now using [ F = m × a ] , we'll find m

=> F = m × a

=> m = F / a

=> m = 40 / 4

=> [ m = 10 kg ] ✔️✔️


♠️ Mass of body is 10 kg




HOPE HELPED..

JAI HIND...

:-)