Physics, asked by Anonymous, 1 year ago

a force of 400N acts on a body revolving at 20km/h if the speed becomes 40km/h after some time then the magnitude of centripetal force is

Answers

Answered by billu004
15
ac1 = V^2/r 
ac2 = (2V)^2/r 
ac2/ac1 = (4V^2/r)*(r/V^2) = 4 
F2 = F1*ac2/ac1= 400*4 = 1600 N 
- then 4 times greater than before !!!

habib003: assalam u alaikum
habib003: kia haal ha apke jii....
habib003: yaad a rahi thi socha aap ko message karlon.....janta hon boht ghusa hongi aap mujh se......lekin phir bhi dil na kaha to message kar diya aap ko......
habib003: aur aap ke shadab khan ke kia haal ha....
habib003: and sorry from the core of my heart that i didn't reply you.....
habib003: maaf kardena plzzzz....
habib003: aur mubark ho apko moderator bnne par......
habib003: meri id mat delete kar dena...
Similar questions