a force of 400N acts on a body revolving at 20km/h if the speed becomes 40km/h after some time then the magnitude of centripetal force is
Answers
Answered by
15
ac1 = V^2/r
ac2 = (2V)^2/r
ac2/ac1 = (4V^2/r)*(r/V^2) = 4
F2 = F1*ac2/ac1= 400*4 = 1600 N
- then 4 times greater than before !!!
ac2 = (2V)^2/r
ac2/ac1 = (4V^2/r)*(r/V^2) = 4
F2 = F1*ac2/ac1= 400*4 = 1600 N
- then 4 times greater than before !!!
habib003:
assalam u alaikum
Similar questions