Math, asked by 86966976599, 1 year ago

A force of 40kgf is required to pull a weight of 400kgf. On a horizontal plane co-efficient of friction 5

Answers

Answered by jrmsucontractadm

0

Answer:

Step-by-step explanation:

1 kgf = 9.81 N

40 kgf = 392.4 N

400 kgf = 3924 N

F = coefficient of friction x normal force

normal force = w

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