Question

A force of 40N acting on a body of mass 10kg changes its velocity from 5m/s to 25m/s; find its acceleration, time, distance cover

Answer 1

F=40N
m=10kg
u=5m/s
v=25m/s

F=ma
40=10a
a=40/10
a=4m/s^2

a=(v-u)/t
4=(25-5)/t
4t=20
t=20/4
t=5s

s=ut+(1/2)at^2
s=5×5+(1/2)4×25
s=25+(2×25)
s=75m