Question

A force of 40N acts on a body for a time interval of 0.5s. The impulse produced is_________.​

Answer 1

Answer:

IMPULSE = FORCE APPLIED x TIME INTERVAL

FORCE APPLIED(F) = 40 N

TIME INTERVAL(DELTA t) = 0.5s

so IMPULSE (J) = F x (Δt)

J = 40 x 0.5

so J = 20 Ns

THUS IMPULSE APPLIED ON THE BODY IS = 20 NEWTON SECOND

IMPULSE COMES UNDER ACTION WHEN A HIGH AMOUNT OF FORCE IS ACTING ON A BODY IN A SHORT TIME INTERVAL

Explanation:

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