Question

A force of 40N applied on a body of mass 10kg with an angle 60degrees then,
what is the work done by the applied force in the 3rd second of its motion

Answer 1

Answer:

work done=360 joules

Explanation:

here ma=40 N

m=10kg

a=4

t=3

u=0

s=ut +1/2at^2

s= 1/2×4×3^2

s=18 meter

work done = force × distance×cos60

work done = 40 × 18 ×1/2

work done = 360 joules