Question

A force of 40n is applied to a body to move at uniform velocity through a distance of 15m in 10s in the direction of the force calculate the power produced

Answer 1

Force = mass× acceleration

F =10 N

mass = 2 kg

a = F/m = 10/2 = 5 m/s²

i)now, u = 0

t = 3 sec

v = u + at = 0 + 3×5 = 15 m/s

ii) initial momentum = mu = 2×0 =0

final momentum = mv = 2×15 = 30 kg m/s

change in momentum = final momentum - initial momentum 

                                   = 30 -0 = 30 kg m/s

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Answer 2

Answer:

Explanation:

Frictional force f = F = 10 N (acting in opposite direction to that of velocity)Distance moved by the body S = 2 m Work done by friction Wf = FS cosθ ... If body moves with constant velocity, the work done by force of friction for a ... Hence the friction force must be equal to the external force applied on the body.