Question

A force of 40N is needed to set a 10 kg steel box moving across a wooden floor.The coefficient of static friction is?

Answer 1

Answer:

The coefficient of static friction is 58 Newton

Explanation:

let, mass= m

acceleration due to gravity= g

force= f

Force needed to move= 40 kg

mass of the steel= 10 kg

Force exerted by the box=mass × acceleration due to gravity

=>f = m × g

=>f = 10 kg × 9.8 m/s²

=>f = 98 N (approx.)

So, force of friction= 98N - 40N

Force of friction= 58N