Physics, asked by black2001eagle11, 9 hours ago

A force of 4800N acts on the surface of area 20cm² normally. What would be the pressure on the surface​

Answers

Answered by Suryaion
6

Answer:

Given,

Force = 4800N

Surface area of contact = 20 cm² = 20/10000 m²

Therefore Using the formula

pressure = force \times area

we get,

pressure= 4800 x 20/ 10000 = 9.6 Pa

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