A force of 4N act on a body of mass 2kg for 4s.the body is at rest find the distance covered in 10s after force starts acting on it.
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force=4N
mass=2kg
time=10s
F/M=a then 4/2=2
a×t=v then 2×0.002=0.004
v×t=s then 0.004×0.002=8×10^(-6)
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