Question

A force of 4N acts on a body at rest of 2kg for 4sec .after next 4sec 2N force operates for 2 sec. Calculate the distance travelled in these 10 sec​

Answer 1

Answer:

Step-by-step explanation:

Force = 4 N., Mass = 2 kg.

Using the Formula,

F = ma , a = F/m    a = 4/2

a = 2 m/s²

Now, u = 0

t = 4 seconds

v - u = at

⇒ v - 0 = 2 × 4

⇒ v = 8 m/s.

Now, v² - u² = 2aS

64 = 2 × 2 × S

S = 16 m.

It is the distance covered in first 4 seconds.

Now, for the distance covered in another 6 seconds.

u =  v of above = 8 m/s.

t = 10 - 4 = 6 seconds.

a = 0 [Force is not acting now]

S = ut + 1/2at²

∴ S = 8 × 6 +  0

∴ S = 48 m.

Total distance covered in 10 seconds = 16 + 48 = 64 m

Answer 2

4N force means acceleration is 4/2 =2

so by distance formula, s= 16m

and for next 2 sec acc. is 1

so distance is 2m

therefore total distance is 16+2 = 18 m.

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