Question

A force of 4N acts on a body of mass 2kg for 4 sec.Assuming the body to be initially at rest. Find it's velocity when the force stops acting on it.​

Answer 1

Acceleration produced

=4/2

=2 m/s/s

we know ,

$a = (v - u) \div t$

$v = u + at$

Since the initial velocity is 0,

v=at

v=2*4

v=8 m/s