Question

a force of 4n acts on a body of mass 2kg for 4 sec assuming the body to be at rest find velocity when force stops acting​

Answer 1

Explanation:

Applied force = 4 N

Mass = 2 kg

Acceleration (a) = Force/ mass

since Force = mass x acceleration

acceleration = 2 m/s²

initial body at rest so u=0

distance covered in Time 4 sec

s=ut+1/2 at²

s= 0*4+1/2 x 2 x 4²

s= 16

now velocity is

v=u+at

v=0+2*4

v=8 m/s

so velocity is 8 m/s

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