Physics, asked by anjuk2309, 10 months ago

A force of 4N acts on a body of mass 2Kg for 4 seconds. Assuming the body to be initially at rest, find (a) its velocity when the force stops acting, (b) the distance covered in 10 seconds after the force starts acting.​

Answers

Answered by Anonymous
9

Hey mate here is your answer,

a) velocity = 8 m/s

b) distance covered in 10 sec = 80 m.

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Answered by shreyascp
1

Explanation:

Total distance covered in 10 seconds = 16 + 48 = 64 m.

A force of 4N acts on a body of mass 2kg for 4 seconds. ... so, velocity of body changes in 4 sec

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