A force of 4N acts on a body of mass 2kg for 4sec . Assuming the body to be initially at rest.Find the distance covered in 10sec after the force starts acting
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a = F / m
= 4 N / 2 kg
= 2 m/s²
S₁ = ut + 0.5at²
= 0 + (0.5 × 2 m/s² × (4 s)²)
= 16 m
v = u + at
= 0 + (2 m/s² × 4s)
= 18 m/s
S₂ = Speed × Time
= 18 m/s × 6 s
= 108 m
Distance travelled in 10 seconds after force starts acting
= S₁ + S₂
= 16 m + 108 m
= 124 m
= 4 N / 2 kg
= 2 m/s²
S₁ = ut + 0.5at²
= 0 + (0.5 × 2 m/s² × (4 s)²)
= 16 m
v = u + at
= 0 + (2 m/s² × 4s)
= 18 m/s
S₂ = Speed × Time
= 18 m/s × 6 s
= 108 m
Distance travelled in 10 seconds after force starts acting
= S₁ + S₂
= 16 m + 108 m
= 124 m
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