A force of 4N acts on a body of mass 2kg for 4sec. Assuming the body to be initially at rest find, (a) its velocity when the force stops acting, (b) distance covered in 10sec after the force starts acting
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v = u + at
v = 0 +2×4
v = 8 ms^-1
s = ut + 1/2at^2
s = 0×10 +1/2×2×10^2
s = 100m
v = 0 +2×4
v = 8 ms^-1
s = ut + 1/2at^2
s = 0×10 +1/2×2×10^2
s = 100m
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