Question

A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s.
(a) How much work is done in 25 s.?

Answer 1

F=5N
m=6kg
v=2.5m/s
t=25s
w=?
F=ma
5=6×a
a=5/6m/s^2
w=m×a/t
=6×5/6/25
=5/25
=1/5

Answer 2

Answer:

312.5 Joules

Explanation:

Speed of object = 2.5 m/s

Time the object moves = 25 s

Since no acceleration is given

Distance = Speed × Time

$\text{Distance}=2.5\times 25=62.5\ m$

Distance traveled by the block is 62.5 m

F = Force on object = 5 N

Work Done is given by the product of force and displacement

$W=F\times s\\\Rightarrow W=5\times 62.5\\\Rightarrow W=312.5\ J$

Work done by the 5 N force is 312.5 Joules