Question

A force of(5+3x)n acting on a body of mass 20 kg along the x-axis displaces it from x=2m to x=6m.The work done by the force is

Answer 1

Answer

44 J

Explanation:

it is variable force so we need to integerate

Answer 2

The work done by the force is 80 Joules.

Explanation:

It is given that,

Force acting on the particle, $F=5+3x\ N$

We need to find the work done by a force displacing a particle from x = 2 m to x = 6 m

The integral form of work done is given by :

$W=\int\limits {F{\cdot}dx}$

Position of particle from x = 2 m to x = 6 m

So, $W=\int\limits^{6}_{2} {5+3x{\cdot}dx}$

$W=5x+\dfrac{3x^2}{2}|_2^6$

$W=5\times 6+\dfrac{3(6)^2}{2}-5\times 2+\dfrac{3(2)^2}{2}$

W = 80 Joules

So, the work done by the force is 80 Joules. Hence, this is the required solution.

Learn more :

Work done

https://brainly.in/question/11759616