Question

A force of 5 N acts of a body at an angle of 60⁰ from the horizontal and displaces it horizontally by 10 m . Force of friction acting on the body of mass 5 kg in this case is 5 N. Find (i) work done by applied force (ii) work done by friction.

PLEASE ANSWER THIS​

Answer 1

Answer:

Hey mate here is your answer...

Explanation:

Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s

2

Work done, W=F.ds

In first second, displacement,

s=

2

1

at

2

s=

2

1

×2×1

s=1m

So, work done,W=10×1=10J

In second second, s=

2

1

×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

Answer 2

Hieeee...

Work = Force Applied × Distance Speed

W = 10 × 5

W = 50N