Question

A force of 5 N acts on a 15 kg body initially at rest. The work
done by the force during the first second of motion of the
body is
(A) 5
(B) 98]
(C) 6)
(D) 75 )​

Answer 1

acc=

15

5

=

3

1

m/s

2

v=u+at

=0+

3

1

×1

3

1

m/s

∴K.E=

2

1

×15×

9

1

=

18

15

=

6

5

J

∴ work done =

6

5

j