Question

a force of 5 N acts on a body such that the direction of the force with horizontal is 60 degree . if the body moves horizontal through a distance of 2m find the work done

Answer 1

given,

force = 5 N

angle formed = 30°

displacement = 6 m

therefore work done ,

= F*s*cosθ

= 5 * 6 * cos (30)

= 30 * 0.866...

= 25.98 J

therefore work done = 25.98 J

Answer 2

Work done = F S cos 60

= 10 *2* 0.5

= 5 J