Question

A force of 5 n acts on a mass of 3 kg for 5 sec what is the rate of change of momentum
a. 5 kg m/sec^2
b. 410 kg m/sec^2
c. 2.5 kg m/sec^2
d. 6 kg m/sec^2

Answer 1

Answer :

Magnitude of applied force = 5N

Mass of body = 3kg

Time interval = 5s

We have to find the rate of change of momentum$.$

★ As per newton's second law of motion,

• Force is defined as the rate of change of linear momentum.
• Force is a vector quantity having both magnitude as well as direction.
• SI unit : N

Mathematically, F = dp/dt

F denotes force

dp/dt denotes rate of change of momentum

⭆ F = dp/dt

⭆ dp/dt = applied force = 5

⭆ dp/dt = 5 kg m/s²

∴ (A) is the correct answer.

Cheers!