a force of 5 n is applied on a 20 kg mass at rest the work done in the third second is
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Explanation:
W = FS cos θ
F = ma
a = F/m
a = 5/20= 1/4 m/s²
therefore, S at t=3 s and a= 1/4 m/s²
S = 0x3 = 1/2(1/4 x 9) since obj was at rest
S= 9/8 m
W= 5 x 9/8 =45/8 = 5.625 Joules
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