Physics, asked by mrcat64, 1 year ago

a force of 5 N on a body of angle 30 with horizontal displacement through 6m distance

Answers

Answered by 6Shivam92

force = 5 N
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J. .........Please mark me as a brainliest.........

mrcat64: your welcome

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