a force of 5 N on a body of angle 30 with horizontal displacement through 6m distance
Answers
Answered by
2
force = 5 N
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J. .........Please mark me as a brainliest.........
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J. .........Please mark me as a brainliest.........
mrcat64:
your welcome
Similar questions