a force of 5 N to an acceleration of 8m/s^2 on a body of mass m1. same force cause an acceleration of 24 m/s^2 on another body of mass m2. if both the bodies are tied together, how much acceleration will be produced by the same force?
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m1=5/8
m2=5/24
total mass=5/8+5/24=20/24=10/12 kg
acc=5/(10÷12)=5×12/10=6m/s^2
m2=5/24
total mass=5/8+5/24=20/24=10/12 kg
acc=5/(10÷12)=5×12/10=6m/s^2
Answered by
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HEY BUDDY..!!!
HERE'S THE ANSWER...
______________________
⏺️ We know
=> F = m × a ________ ( 1 )
⏭️ Let take first body of mass M1
=> F = 5 N
=> a = 8 m / s^2
⏺️ According to eq. 1
=> M1= F / a
=> M1 = 5 / 8 kg
⏭️ Now with second body with mass M2
=> F = 5 N
=> a = 24 m / s^2
So
=> M2 = 5 / 24
A.T.Q.
⏺️ Mass of two bodies is combined
So, Let M1 + M2 = M
=> M1 + M2 = ( 5 / 8 + 5 / 24 ) kg
=> M = 20 / 24 kg
F = 5 N
a = ?
⏺️ According to eqn 1
=> a = F / M
=> a = 5 / 20 / 24
=> a = 6 m / s^2
HOPE HELPED..
GOOD NIGHT..
:-)
HERE'S THE ANSWER...
______________________
⏺️ We know
=> F = m × a ________ ( 1 )
⏭️ Let take first body of mass M1
=> F = 5 N
=> a = 8 m / s^2
⏺️ According to eq. 1
=> M1= F / a
=> M1 = 5 / 8 kg
⏭️ Now with second body with mass M2
=> F = 5 N
=> a = 24 m / s^2
So
=> M2 = 5 / 24
A.T.Q.
⏺️ Mass of two bodies is combined
So, Let M1 + M2 = M
=> M1 + M2 = ( 5 / 8 + 5 / 24 ) kg
=> M = 20 / 24 kg
F = 5 N
a = ?
⏺️ According to eqn 1
=> a = F / M
=> a = 5 / 20 / 24
=> a = 6 m / s^2
HOPE HELPED..
GOOD NIGHT..
:-)
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