Question

a force of 5 Newton acting on a body at an angle of 30 degree with the horizontal Direction this place it horizontally through a distance of 6 m calculate the work done

Answer 1

hallo friend your answer is given below.

work done = force × disp.. × cos0

= 5 × 6 × cos 30

= 30 × underoot 3 / 2

= 15 underoot 3 joules .

Answer 2

Given :

Force applied , F = 5 N .

Angle from horizontal surface , $\theta=30^o$ .

To Find :

The work done in moving the object to 6 m .

Solution :

We know , work done is given by :

$W=Fd\ sin\ \theta\\\\W=5\times 6\times sin \ 30^o\\\\W= \dfrac{30}{2}\ J\\\\W=15\ J$

Therefore ,  work done in moving the object to 6 m is 15 J .

To Find :

Work , Power and Energy

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