A force of 5 newton acts on a 15 kilo body initially at rest the work done by the force during the first second law of motion of a body is
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Here you need Work Energy Theorem.
Acceleation=5/15=0.33m/s^2
velocity at end of the first second=0.33m/s
Now work done will be equal to change in kinetic energy.
Kinetic energy=0.5×15×0.33×0.33=5/6J
so work done will be 5/6J
Acceleation=5/15=0.33m/s^2
velocity at end of the first second=0.33m/s
Now work done will be equal to change in kinetic energy.
Kinetic energy=0.5×15×0.33×0.33=5/6J
so work done will be 5/6J
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