Question

A force of 50 dynes is acted on a body of mass 5g
which is at rest for an interval of 3 sec., then impulse
is-
(1) 0.15 x 10 Ns (2) 0.98 x 10-Ns
(3) 1.5 x 10 Ns
(4) 2.5 x10- Ns​

Answer 1

Explanation:

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Answer 2

The impulse imparted on the body is $1.5\times 10^{-3}\ N-m$.

Explanation:

It is given that,

Force acting on the body, F = 50 dynes = 0.0005 N

Mass of an object, m = 5 g = 0.005 kg

Time, t = 3 s

We know that the product of force and time is equal to the impulse of an object. Also, impulse is equal to the change in momentum of an object.

$J=F\times t$

$J=0.0005 \times 3$

J = 0.0015 N-m

$J=1.5\times 10^{-3}\ N-m$

So, the impulse imparted on the body is $1.5\times 10^{-3}\ N-m$. Hence, this is the required solution.

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