Question

A force of 50 kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction., find the force exerted on the large piston, if the diameter of piston is 10 cm and 20cm respectively.​

Answer 1

Answer:

We know that Pressure on both the Piston should be same,

∴Pressure on smaller Piston=Pressure on larger Piston

Area of smaller

Force on smaller

=

Area of larger

Force on larger

∴ Force on Larger=

Area of smaller

Force on smaller

×Area of larger

⇒

2.5×2.5×3.14

50

×12.5×12.5×3.14=1250kgf

Answer 2

Explanation:

the correct answer is 1250 kgf.