Question

a force of 50 N acts on a body and moves it a distance of 4 m on a horizontal surface . calculate the work done if the direction of forces is at an angle of 60 to the horizontal surface.

Answer 1

WD=?
F=50N
S=4m
cos60=1/2

WD =F*S*cos60
= 50×4×1/2
=100Joules
WD=100J

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Answer 2

force=50N
displacement=4m
angle=60°
.
.
we know that...

$work \: done = fs cos60$
work done=50N*4m*1/2
work done = 100joule...