Question

A force of 50 N acts on a body initially at rest. Find the momentum of the body at 3 sec and 6 sec after the force begins to act

Answer 1

F = P / Δt

P = F * Δt

P = 50 * 3

P = 150 kg*m/s

Answer 2

Answer:

Let mass m

F = 50N

U = 0

t*1 = 3 sec

t*2 = 6 sec

Using formulaes

P*1 = mu

= m×0

P*1 = 0

F = P*2 -P*1

------------

T

50 = p*2 - 0

----------

6-3

50 ×3 = p*2 -0

150 = p*2

P* 2= Final momentum

Easy way for class 9

Here " * " is playing role of power ex- P*2-P*1 it means p(momentum) ki power 1 telling that formulae of change in momentum .