Question

A force of 50 N acts on an area of 60 cm^2. Calculate the pressure
produced.​

Answer 1

Solution :-

Given ,

$\star$Force = 50 n

$\star$Area = 60 cm² = 0.006 m²

We know that ,

$\sf \large\fbox{ \fbox{Pressure = \frac{Force}{Area } }}$

$\sf \implies Pressure = \frac{50}{0.006} \\ \\\sf \implies Pressure = 8333.3 \: \: Pascal$

Hence , 8333.3 Pascal is required value of pressure

Answer 2

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

From the Question,

• Force,F = 50 N

• Area,A = 60 cm² = 0.006 m²

Using Dimensional Analysis,

$\displaystyle{\sf{A = 60{cm}^{2} \times \frac{1{m}^{2}}{1000 \ {cm}^{2}}}}} \\ \\ \rightarrow \sf{A = 0.006 {m}^{2}}$

We know that,

$\boxed{\sf{pressure \: = \frac{force}{area} }}$

Putting the values,we get:

$\sf{p = \frac{50}{0.006} } \\ \\ \implies \: \sf{p = \frac{50}{6 \times 10 {}^{ - 3} } } \\ \\ \implies \: \sf{p = \frac{8.33}{10 {}^{ - 3} } } \\ \\ \huge{ \implies \: \sf{p = 8.3 \times 10 {}^{3} Pascals}}$