Question

a force of 50 newton acts on a body for 1/10 seconds. find the change in momentum ​

Answer 1

Answer:

20............. ................

Answer 2

Answer:

$\sf \large \implies Force = \frac{dp}{dt} \\ \\ \sf \large \implies \: where  \frac{dp}{dt} is \: the \: rate \: of \: change \\ \sf \large\: of \: linear \: momentum \\ \\</p><p></p><p> \sf \implies { \boxed{ \bold{ \pink{Given, F = 50N}}}} \\ \\ \sf \implies{ \boxed{ \red{ \bold {dt = 1/10 s}}}}</p><p></p><p> \\ \\ \sf \therefore change \: in \: linear \: momentum, \\ \\</p><p></p><p> \sf \implies{ \boxed{dp = F \times dt}} \\ \\</p><p></p><p> \sf \implies{ \boxed{50 \times \frac{1}{10} }} \\ \\</p><p></p><p> \sf \implies { \boxed{ \boxed { \green{ \bold5 Kg m/s}}}} </p><p></p><p>$