Question

A force of 50 newton acts on a body of mass 10 kg initially rest of 2s determines it's acceleration final velocity and the distance covered by it

Answer 1

F = m*a
50 = 10*(v-0)/2
50 = 5*v
{v = 10 m/s}•••{Final velocity}

v = u + at
10 = 0 + 2a
2a = 10
{a = 5 m/s²}•••{Acceleration}

s = ut + 1/2 at²
s = 0 + 1/2*5*4
{s = 10 metres}•••{Distance covered}

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