Physics, asked by yogichaudhary, 1 year ago

A force of 50 newton is applied on a nail of area 0.001 square cm .Then its thrust is?

Answers

Answered by Vaiarathe
5

F = 50 N
A = 0.001 cm^2 = 0.0000001 m^2

Thrust = F/A = 50/ 0.0000001 = 5×10^8 Pa = 500 MPa

Thrust is 500 MPa

Answered by Friendshipbrain
2
Hey dear here is your answer

Thrust (or Force) per unit area is called pressure. 
Force ( Thrust) = F = 50 N 
Area = A = 0.001 sq. cm.= 10^(-3) cm² = 10^(- 7) m² 
Pressure = P = F/A = 50/{10^(-7)} = 5*(10^8) N/m² = 5*(10^8) pascal

Please mark me as brainliest,Thank you and follow me.
Similar questions