A force of 50 newton is applied on a nail of area 0.001 square cm .Then its thrust is?
Answers
Answered by
5
F = 50 N
A = 0.001 cm^2 = 0.0000001 m^2
Thrust = F/A = 50/ 0.0000001 = 5×10^8 Pa = 500 MPa
Thrust is 500 MPa
Answered by
2
Hey dear here is your answer
Thrust (or Force) per unit area is called pressure.
Force ( Thrust) = F = 50 N
Area = A = 0.001 sq. cm.= 10^(-3) cm² = 10^(- 7) m²
Pressure = P = F/A = 50/{10^(-7)} = 5*(10^8) N/m² = 5*(10^8) pascal
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Thrust (or Force) per unit area is called pressure.
Force ( Thrust) = F = 50 N
Area = A = 0.001 sq. cm.= 10^(-3) cm² = 10^(- 7) m²
Pressure = P = F/A = 50/{10^(-7)} = 5*(10^8) N/m² = 5*(10^8) pascal
Please mark me as brainliest,Thank you and follow me.
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