Question

.A force of 500 dynes acts on a mass of 0.05 kg over a distance ola
m. Assuming that the mass is initially at rest, find the final velocity and time for which
the force acts​

Answer 1

Answer:

Explanation:

F=500*10^-5=0.005

m=0.05

F=Ma  --->a=F/M=0.005/0.05=0.1

S=1

u=0

v=?

V2-u2=2as

V2-0=2*0.1*1

v=under root 2