Question

A force of 500 dynes is applied on an area
of 20 cm. Calculate the pressure exerted.​

Answer 1

Answer:

pressure =force/area

Explanation:

given ,

force=500dynes

=500×10^(-5) Newtons

area=20cm

=20×10^(-2) metres

Therefore,

pressure = force / area

= [500×10^(-5)] / [20×10^(-2)]

=25×10^(-3)

=0.025 N/ m^2

HOPE THIS HELPS YOU......

Answer 2

Answer:

The Pressure exerted is 2.5Pa

Explanation:

Given that,

The total force exerted on given area=500dyne

ThebArea on which force was exerted =20sq.cm

We first convert the force and Area into SI Units

Force in SI system is

F = 500 \times 10 {}^{ - 5} N = 5 \times 10 {}^{ - 3} N

Area in SI System is

$A = 20 \times 10 {}^{ - 4} m {}^{2} = 2 \times 10 {}^{ - 3} m {}^{2}$

Therefore,the pressure exerted is calculated by relation

P = \frac{F}{A}

Substituting given values,we get

P = \frac{5 \times 10 {}^{ - 3} }{2 \times 10 {}^{ - 3} } = 2.5Pa

Therefore,Pressure exerted is 2.5Pa

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