Physics, asked by khush2336a, 6 hours ago

A force of 500 dynes is applied
on an area of 20 cm2. Calculate the pressure exerted,

Answers

Answered by gursharanjali
1

Answer:

pressure =force/area

Explanation:

given ,

force=500dynes

=500×10^(-5) Newtons

area=20cm

=20×10^(-2) metres

Therefore,

pressure = force / area

= [500×10^(-5)] / [20×10^(-2)]

=25×10^(-3)

=0.025 N/ m^2

Answered by Anonymous
16

Given:-

  • Force Applied= 500Dynes=500x10^-5N.
  • Area=20cm²=20x10^-2m².

To Find:-

  • Pressure exerted.

Solution:-

We Know that

pressure \: exerted =  \frac{force \: applied}{area}

So,

 =  > p =  \frac{500 \times  {10}^{ - 5}  N }{20 \times  {10}^{ - 2} {m}^{2}  }

 =  > p =  \frac{50\times  {10}^{ 2}  N }{2 \times  {10}^{ 5} {m}^{2}  }

=  > p =  \frac{25\times  {10}^{ 2}  N }{  {10}^{ 5} {m}^{2}  }

=  > p =  \frac{25N }{  {10}^{ 3} {m}^{2}  }

\therefore p = 0.0025N {m}^{ - 2}

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