Question

A force of 500 N acting on a car of mass 100 kg enable it to move with a uniform velocity of 60kmh^-1 over a horizontal road.The co-efficient of friction between the tyres and ground is[g=10m/s]​

Answer 1

Solution

F=500 Newton

m=100kg

v=60kmph

we know..........

R=mg

and

F=u(k)×R

=>F=u(k)×mg

=>u(k)=F/mg

=>u(k)=500/(100×10)

=>u(k)=0.5

hope this helps you...