Question

a force of 500 Newton acts on the surface area 12 normally what would the pressure on
surface​

Answer 1

GIVEN :-

• Force acting on the surface is 500N
• Surface area = 12 m²

TO FIND :-

• Pressure acting on the surface

SOLUTION :-

Pressure acting is given by ,

$\large {\underline {\boxed {\bigstar {\red {\sf{ \: P = \frac{F}{a} }}}}}}$

Where ,

• F is force acting
• a is area

We are given ,

• F = 500 N
• a = 12 m²

$\implies \sf \: P = \frac{500 \: N}{12 \: {m}^{2} } \\ \\ \implies {\underline {\boxed {\blue {\sf {\: P= 41.6 \: N {m}^{ - 2} }}}}}$

∴ The pressure acting on the surface is 41.6 N/m²

ADDITIONAL INFO :-

◉ Pressure is defined as force acting perpendicularly per unit area.Pressure is a scalar quantity hence it has magnitude but no direction

◉ Common units of pressure is N/m² , Pa

◉ Pressure has a dimensional formula of

[M L⁻¹ T⁻²]

◉ Types of pressure ,

• Absolute pressure
• Gauge pressure
• Atmospheric pressure
• Differential pressure

◉ Pressure is directly proportional to Force acting and inversely proportional tothe surface area

EXAMPLE :-

Let's Consider a most familiar example.Consider two knifes such that one should have less surface area (Sharp knife) and the other should have more surface area (blunt knife). When u try to cut anything using these two knifes , u will experience that the knife having less contact area takes less time to react than the knife having more surface area.

Hence, Pressure is indirectly proportional to area of contact and directly proportional to Force acting.

◉ Some Relations :-

$\to \rm Pressure \propto h = Depth \\ \\ \to \rm Pressure \propto d = Density \\ \\ \to \rm Pressure \propto g \\ \rm \: (g = acceleration \: due \: to \: Gravity) \\ \\ \to \rm Pressure \propto \dfrac{1}{Area} \\ \\ \to \rm Pressure \propto Force$

Answer 2

Answer:

GIVEN :-

Force acting on the surface is 500N

Surface area = 12 m²

TO FIND :-

Pressure acting on the surface

SOLUTION :-

Pressure acting is given by ,

\large {\underline {\boxed {\bigstar {\red {\sf{ \: P = \frac{F}{a} }}}}}}

★P=

a

F

Where ,

F is force acting

a is area

We are given ,

F = 500 N

a = 12 m²

\begin{gathered} \implies \sf \: P = \frac{500 \: N}{12 \: {m}^{2} } \\ \\ \implies {\underline {\boxed {\blue {\sf {\: P= 41.6 \: N {m}^{ - 2} }}}}}\end{gathered}

⟹P=

12m

2

500N

⟹

P=41.6Nm

−2

∴ The pressure acting on the surface is 41.6 N/m²

ADDITIONAL INFO :-

◉ Pressure is defined as force acting perpendicularly per unit area.Pressure is a scalar quantity hence it has magnitude but no direction

◉ Common units of pressure is N/m² , Pa

◉ Pressure has a dimensional formula of

[M L⁻¹ T⁻²]

◉ Types of pressure ,

Absolute pressure

Gauge pressure

Atmospheric pressure

Differential pressure

◉ Pressure is directly proportional to Force acting and inversely proportional tothe surface area

EXAMPLE :-

Let's Consider a most familiar example.Consider two knifes such that one should have less surface area (Sharp knife) and the other should have more surface area (blunt knife). When u try to cut anything using these two knifes , u will experience that the knife having less contact area takes less time to react than the knife having more surface area.

Hence, Pressure is indirectly proportional to area of contact and directly proportional to Force acting.

◉ Some Relations :-

\begin{gathered}\to \rm Pressure \propto h = Depth \\ \\ \to \rm Pressure \propto d = Density \\ \\ \to \rm Pressure \propto g \\ \rm \: (g = acceleration \: due \: to \: Gravity) \\ \\ \to \rm Pressure \propto \dfrac{1}{Area} \\ \\ \to \rm Pressure \propto Force \end{gathered}

→Pressure∝h=Depth

→Pressure∝d=Density

→Pressure∝g

(g=accelerationduetoGravity)

→Pressure∝

Area

1

→Pressure∝Force