Question

a force of 50n acts on a body for 0.3 sec,then what is the impulse in Ns​

Answer 1

Answer:

Explanation:

Force acting on the body  F=50 dynes=50×10  

−5

 N

Time of action of force  t=3 s

Thus impulse  I=Ft

∴ I=50×10  

−5

×3=1.5×10  

−3

 N s

Answer 2

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