Physics, asked by samdina6861, 9 months ago

A force of 50n acts on a body of mass 10kg at rest its velocity after 5 sec if the same force acts is

Answers

Answered by minisha0
19

Answer:

25m/s

Explanation:

f= ma

50n= 10×v-0/5

50= 2v

25=v

Answered by agis
16

The velocity of the body after 5 s is 25 m/s.

Explanation:

The force acts on a body, F = 50 N.

The mass of the body, m = 10 kg.

The force is given as

F = ma

Here a is the acceleration due to gravity.

Substitute the values, we get

50 N = 10 kg x a

a = 5 m/s^2

The acceleration is given as

 a=\frac{v_f-v_i}{\Delta t}

We take initial velocity zero because body initially at rest.  

so ,    

5m/s^2=\frac{v_f-0}{5s}

v_f=25 m/s

Thus, the velocity of the body after 5 s is 25 m/s.

#Learn More: Force.

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