Question

A force of 50N acts on a particle at an angle of 60 degree with horizontal. Calculate it's two rectangular components

Answer 1

Answer:

Horizontal component of the force, $F_1$ = 25N

Vertical component of the force, $F_2$ = 43.30 N

Explanation:

Magnitude of force = 50N

Angle between the force and the horizontal axis = 60 degrees

The two rectangular components are the horizontal component and the vertical component.

Horizontal component of the force, $F_1$ = $F cos\theta$ = $50\times \cos 60$ = $50\times \frac{1}{2}=25N$

Vertical component of the force, $F_2=F\sin \theta =F\sin 60$ = $50\times \frac{\sqrt{3}}{2}$ = 43.30 N