Question

A force of 50N is acting on a body of mass 200kg moving with a speed of 15 m/s.How long does the body take to stop? what distance will it cover before coming to rest?​

Answer 1

Answer:

as we know,

F =ma

50=200 X a

=> a = 50/200

=> a= (1/4) m/s²

we have to find how long distance it will cover before stop,

v² = u² + 2as

=> 0² = 15² + 2 X (1/4) X S

=> (S/2) + 225 = 0

=>S= -225 x 2

=>S= 450m

time take to stop,

v = u + at

=> 0 = 15+ (1/4) t

=>t/4 = -15

=> t = -15 X 4

=> t = 60sec

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